Arigid, sealed tank initially contains 2000 kg of water at 30 °c and atmospheric pressure. determine: a) the volume of the tank (m3 ). later, a pump is used to extract 100 kg of water from the tank. the water remaining in the tank eventually reaches thermal equilibrium with the surroundings at 30 °c). determine: b) the final pressure (kpa).

Given:

mass of water, m = 2000 kg

temperature, T = = 303 K

extacted mass of water = 100 kg

Atmospheric pressure, P = 101.325 kPa

Solution:

a) Using Ideal gas equation:

PV = mT                                        (1)

where,

V = volume

m = mass of water

P = atmospheric pressure

R= Rydberg's constant = 8.314 KJ/K

M = molar mass of water = 18 g/ mol

Now, using eqn (1):

Therefore, the volume of the tank is

b) After extracting 100 kg of water, amount of water left, m' = m - 100

m' = 2000 - 100 = 1900 kg

The remaining water reaches thermal equilibrium with surrounding temperature at T' = = 303 K

At equilibrium, volume remain same

So,

P'V = m'T'

Therefore, the final pressure is P' = 96.258 kPa

b. check your rearview mirror

explanation:

answer:

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