The 10 foot wide circle quarter gate ab is articulated at a. determine the contact force between the gate and the smooth surface at b due to the pressure of the water acting on the gate. use γ = 62.4 lb / ft^3 for the water. r=8 ft

Explanation:

Given that

R=8 ft

Width= 10 ft

We know that hydro statics force given as

  F=ρ g A X

ρ is the density of fluid

A projected area on vertical plane

X is distance of center mass of projected plane from free surface of water.

Here

X=8/2  ⇒X=4 ft

A=8 x 10=80  

So now putting the values

F=ρ g A X

F=62.4(32.14)(80)(4)

answer: 500 wph.

explanation:

sorry what a asnns

explanation: