Air in a rigid tank is initially at 320 k and 130 kpa. heat is added until the final pressure is 438 kpa. what is the change in entropy of the air? do not assume constant specific heats

Change in entropy is 0.8712 kJ/kgK

Given:

Initial Temperature, T = 320 K

Initial Pressure, P = 130 kPa

Final Pressure, P' = 438 kPa

Solution:

Here, a rigid tank is considered, therefore, the volume of the tank is constant and for a process at constant volume:

Pressur, P ∝ Temperature, T

Therefore,

Now, change in entropy is given by:

Therefore, change in entropy is 0.8712 kJ/kgK

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