It has a piece of 1045 steel with the following dimensions, length of 80 cm, width of 30 cm, and a height of 15 cm. in this piece it is desired to make a groove 80 cm long, with a width of 8 cm and a depth of 10 cm,. assumes that for this operation an end mill tool of 4 mm diameter, the axial cutting depth, will be used it will be 20 mm. how much material will have been removed in cubic mm at 3 minutes of machining if you have an advance of 0.001166 mts / sec?

material remove in 3 min is 16790.4 mm³/s

Explanation:

given data

length L = 80 cm = 800 mm

width W = 30 cm

height H = 15 cm

make grove length = 80 cm

width = 8 cm

depth = 10 cm

mill toll diameter = 4 mm

axial cutting depth = 20 mm

to find out

How much material removed in 3 minutes

solution

first we find time taken for length of advance that is

time =

here advance is given as 0.001166 mts / sec

so  time =

time = 686.106 seconds

now we find material remove rate that is

remove rate = mill toll rate × axial cutting depth × advance

remove rate = 4 × 20×0.001166 ×1000

remove rate = 93.28 mm³/s

so

material remove in 3 minute = 3 × 60 = 180 sec

so material remove in 3 min = 180 × 93.28

material remove in 3 min is 16790.4 mm³/s

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hope this is what you're talking about

answer: a

a is the answer