Steam at 1400 kpa and 350°c [state 1] enters a turbine through a pipe that is 8 cm in diameter, at a mass flow rate of 0.1 kg⋅s−1. the exhaust from the turbine is carried through a 15-cm-diameter pipe and is at 50 kpa and 100°c [state 2]. what is the power output of the turbine?
h1 = 3150.7 kj/kg v1 = 0.2004 m3/kg
h2 = 2682.6 kj/kg v2 = 3.4181 m3/kg

Power output,

Given:

Pressure of steam, P = 1400 kPa

Temperature of steam,

Diameter of pipe, d = 8 cm = 0.08 m

Mass flow rate,

Diameter of exhaust pipe,

Pressure at exhaust, P' = 50 kPa

temperature, T' =  

Solution:

Now, calculation of the velocity of fluid at state 1 inlet:

Now, eqn for compressible fluid:

Now,

Now, the power output can be calculated from the energy balance eqn:

answer:

explanation:

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