Apiston cylinder contains air at 600 kpa, 290 k and a volume of 0.01 m3m3. a constant pressure process gives 18 kj of work out. what is the final temperature? you may assume ideal gas.

1160 K.

Explanation:

Given that

Initial

Pressure P =600 KPa

Temperature T =290 K

Volume V =0.01

If we assume that air is s ideal gas the

P V = mRT

R=0.287 KJ/kg.k

now by putting the values in above equation

600 x 0.01 = m x 0.287 x 290

m=0.07 kg

The work out at constant pressure given as

At constant pressure

So the final temperature is 1160 K.

answer:

person b

explanation:

answer:

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