(a) if 15 kw of power from a heat reservoir at 500 k is input into a heat engine with an efficiency of 37%, what is the power output? (b) what is the temperature of the cold reservoir?

(A) Power output will be 5.55 KW (b) lower temperature will be 315 K

Explanation:

We have given efficiency of heat engine = 0.37

Input power = 15 KW

Temperature of heat reservoir

(A) We know that

So  [text]0.37=\frac{output}{15}[text]

Output = 5.55 KW

(B) We also know that [text]\eta =1-\frac{T_L}{T_H}0.37=\frac{output}{15}[text], here  is lower temperature and is higher temperature

So

answer:

i answer later k

explanation:

If the temperature goes on increasing with respect to the length (i.e temperature gradient)then it is called positive heat transfer. If the temperature gradient decreases then it is called negative heat transfer.

Explanation: