Arigid tank holds 10 lbm of 160 °f water. if the quality of the water is 0.5 then what is the pressure in the tank and volume of the tank?

The pressure and volume of the tank are 4.74703 psi and 385.968 ft³ respectively.

Explanation:

Volume is constant as the tank is rigid. Take the saturation condition of water from the steam table for pressure at 160°F.  

Given:  

Mass of the water is 10 lb.

Dryness fraction is 0.5.

Temperature of water is 160°F.  

From steam table at 160°F:  

The pressure in the tank is 4.74703 psi.  

Specific volume of saturated water is 0.0163918 ft³/lb.  

Specific volume of saturated steam is 77.1773 ft³/lb.  

Calculation:  

Step1  

From steam table at 160°F:  

The pressure in the tank is 4.74703 psi.  

Step2  

Specific volume of tank is calculated as follows:  

v=38.5968 ft³/lb.  

Step4  

Volume is calculated as follows:  

V=385.968 ft³.  

Thus, the pressure and volume of the tank are 4.74703 psi and 385.968 ft³ respectively.