The input shaft to a gearbox rotates at 2300 rpm and transmits a power of 42.6 kw. the output shaft power is 34.84 kw at a rotational speed of 620 rpm. determine the torque of the input shaft shaft, in n-m.

Torque at input shaft will be 176.8695 N-m

Explanation:

We have given input power

Angular speed = 2300 rpm

For converting rpm to rad/sec we have multiply with

So

We have to find torque

We know that  power is given by , here is torque and is angular speed

So

So torque at input shaft will be 176.8695 N-m

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )