Turpentine flows through a 12-nominal schedule 40 pipe. what is the flow rate that corresponds to a reynolds number of 2000?

flow rate is 8.0385 × m³/s or 12.741 gpm

Explanation:

given data

12-nominal schedule 40 pipe

Reynolds number = 2000

to find out

What is the flow rate

solution

we know the diameter of 12-nominal schedule 40 pipe is

Diameter = 12.75 inch

D = 0.32385 m

and

dynamic viscosity of Turpentine is = 0.001375 Pa-s

and Density of Turpentine is 870 kg/m³

so

Reynolds number is express as

Re =

here ρ is density and D is diameter and V is velocity and µ is viscosity

so put here all value

2000 =

V = 9.7619 × m/s

and

flow rate is

Q = V  × A

here A is area and Q is flow rate

Q = 9.7619 ×  ×  

Q = 8.0385 × m³/s

so flow rate is 8.0385 × m³/s or 12.741 gpm

answer:

what

explanation: