Propane burns at an equivalence ratio (er) of 0.6, determine actual air-fuel ratio. if excess air is 5%, what will be the actual air fuel ratio?

when 5% excess air is supplied, moles of air supplied/moles of fuel =

Explanation:

Equivalence ratio = 0.6

Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR

combustion reaction of propane is

From above reaction,  1 mole of propane, from the reaction, 5  moles of oxygen required,  

we know that air contains 21% O_2 and 79% N_2,

Therefore, moles of air based on stoichiometry

Theoretical air to fuel ratio

Given

Actual Air Fuel Ratio

when 5% excess air is supplied, moles of air supplied/moles of fuel =

i mean i gues

explanation: