3. (a) (5 points) suppose n packets arrive simultaneously to a link at which no packets are currently being transmitted or queued. each packet is of length l and the link has transmission rate r. what is the average queuing delay for the n packets? (b) (5 points) now suppose that one of such n packets arrives to the link every l/2r seconds. what is the average queuing delay of a packet?

(N-1) × (L/2R) = (N-1)/2

Explanation:

let L is length of packet

R is rate

N is number of packets

then

first packet arrived with 0 delay

Second packet arrived at = L/R

Third packet arrived at = 2L/R

Nth packet arrived at = (n-1)L/R

Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R

Now

L / R = (1000) / (10^6 ) s = 1 ms

L/2R = 0.5 ms

average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2

the average queuing delay of a packet = 0 ( put N=1)

answer:

a

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answer:

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