Apipeline (nps = 14 in; schedule = 80) has a length of 200 m. water (15℃) is flowing at 0.16 m3/s. what is the pipe head loss for the water supply over a distance of 200 m? hint: use an iterative approach for the empirical equation.

Head loss is 1.64

Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

We know,

where, f = Darcy friction factor

V = flow velocity

g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

obtained Darcy friction factor  

calculate Reynold number (Re) ,

where, = density of water

= Dynamic viscosity of water at 15 degree  C = 0.001 Ns/m2

so reynold number is

            = 6.4 x 10^5

For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = 1.64 m

answer:

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