Apiston cylinder containing 0.2 kg of air undergoes a process where pressure and volume are related by the expression p=cv where c is a constant value. if the initial pressure is 0.1 mpa and the initial temperature is 25 °c, determine the work done in units of kj for the final volume to be four times the initial volume.

Work = 51,33 kJ

Explanation:

According to the ideal gas equation, the initial volume is calculated as follows:

Then the work for an isobaric process can be calculated using the following expression:

And considering that,

The work can be calculated as follows:

158.57 kJ

Explanation:

We can assume air is an idela gas and the ideal gas law applies.

And we know that:

WE can assume the process is isothermal

Therefore the work:

W=mRTln(V₂/V₁)

We can determine the constant C as:

P₂ is 0.01 kPa

V₂=0.005

V₁=50

The total work is 158.57 kJ

answer:

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explanation: