Steam enters an adiabatic diffuser at 200 kpa and 150°c with a velocity of 600 m/s. determine the minimum velocity that the steam can have at the outlet when the outlet pressure is 400 kpa.

m/s

Explanation:

Given

At inlet :

Pressure, = 200 kPa

Temperature,   = 150°C

Velocity, = 600 m/s

Now from steam table at super heated region, we know,

= 2769.1 KJ/kg

Now at = 400 kPa at saturated region.

For maximum velocity at exit, steam should be at saturated vapour at exit.

Therefore, at = 400 kPa, = = 2739.8 KJ/kg

Therefore,

m/s

Hence the answer is m/s

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explanation: