Aslab-milling operation will take place on a 6061 aluminum (free machining) 12" long and 2" wide piece of material. a spiral, helical cutter 3" in diameter with 12 teeth will be used. if the feed per tooth (f) is 0.007 inches/tooth and the cutting speed (v) is 444 sfm. find the machining time.

t=0.32 min

Explanation:

Given that

W= 2 in

L= 12 in

D= 3 in

Z= 12 teeth

Speed ,V= 444 SFM

We know that

1 SFM = 0.00508 m/s

So

444 SFM = 2.25 m/s

V= 2.25 m/s

1 m/s= 39.37 in/s

V =88.58 m/s

We know that

N=\dfrac{60\times 88.58}{\pi \times 3}

N=563.91 RPM

Compulsory approach ,X

X=3.33 in

Machining time,t

t=0.32 min

fanswer:

explanation:

f

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explanation:

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