Acurrent of 0.3 ampere flows through a 2-ohm resistor. at what rate does the resistor release heat?
oa 6.7 w
b.
0.15 w
oc 0.6 w
d. 0.18 w
e.
0.5 w
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D. 018 W

Explanation:

Power = current × voltage

P = IV

From Ohm's law, voltage = current × resistance

V = IR

Therefore:

P = I²R

Given I = 0.3 A and R = 2 Ω:

P = (0.3 A)² (2 Ω)

P = 0.18 W

import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(

answer:

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