Bananas are to be cooled from 28°c to 12°c at a rate of 1140 kg/h by a refrigerator that operates on a vapor-compression refrigeration cycle. the power input to the refrigerator is 9.8 kw. determine (a) the rate of heat absorbed from the bananas, in kj/h, and the cop, (b) the minimum power input to the refrigerator, and (c) the second-law efficiency and the exergy destruction for the cycle. the specific heat of bananas above freezing is 3.35 kj/kg·°c.

A)

B)

C) Second law efficiency 4.85%

exergy destruction for the cycle = 9.3237 kW

Explanation:

Given data:

degree celcius

degree celcius

Power to refrigerator = 9.8 kW

Cp = 3.35 kJ/kg degree C

b)

wil be max when COP maximum

taking surrounding temperature T_H = 20 degree celcius

we know that

c) second law efficiency

exergy destruction os given as

                                                         = 9.8 - 0.473 = 9.3237 kW

i mean i gues

explanation:

answer:

yes

explanation: