Let a be the set of words in the oxford english dictionary (oed). for each positive integer j, define aj to be the set of all words with j letters in the oed. for example, the word "discrete" is an element of a8 because the word "discrete" has 8 letters. the longest word in the oed is "" which has 45 letters. you can assume that for any integer i in the range 1 through 45, there is at least one word in the oed that has i letters. do the sets a1, …, a45 form a partition of the set of words in the oed?

answer: jesus loves you

explanation:

answer: a

a is the answer

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)