Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nc . part a what is the electric field strength inside the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part b what is potential difference across the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer part c what is the electric field strength inside the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part d what is the potential difference across the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer provide feedback next

A.

B. 151.2 V

C.

D. V = 302.4 V

Solution:

As per the question:

Area of the plates of the parallel plate capacitors, A =

Charge on the plates of the capacitor,

Now,

(A) To calculate the electric field strength, E when the separation distance, d = 1.00 mm = :

(B) To calculate potential difference between the plates:

(C) Electric field strength when spacing is 2 mm, i.e., :

Since, the above expression of the electric field shows that it does not depend on the separation distance between the plates thus it will remain same, i.e.,

(D) Potential difference across the capacitor when d = :

V = Ed =

the correct answer is c.stops after infancy and childhood.

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