An insulated steady-flow mixing chamber has two inlets and 1 outlet. at inlet 1, the mass flow rate is 0.08 kg/s. at inlet 2, the mass flow rate is 0.15 kg/s. the average velocity at the outlet is 12.84 m/s. the area of the outlet is 0.01 m2. what is the specific volume of the outlet fluid (m3/kg) (3 significant figures)?

the specific volume will be ρ = 1.791 kg/m³

Explanation:

From conservation of mass:

m₃ out =m₁ in + m₂ in

m₃ out =m₁ in + m₂ in =0.08 kg/s + 0.15 kg/s = 0.23 kg/s

the volumetric flow rate q at the outlet will be

q = v*A , where v= velocity at the outlet and A= area of the outlet

q= 12.84 m/s * 0.01 m² = 0.1284 m³/s

the specific volume of the outlet fluid will be

ρ = m₃ out / q = 0.23 kg/s / 0.1284 m³/s = 1.791 kg/m³

ρ = 1.791 kg/m³

answer:

ask me the quest

explanation:

answer:

ya

explanation:

sure ill do it