Estimate the remaining life in revolutions of a 02-30 mm angular-contact ball bearing already subjected to 216000 revolutions with a radial load of 15 kn, if it is now to be subjected to a change in load to 25.05 kn. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.

Radial load of 15 kN, remaining life is 2478519 rev

When load is 25.05, we have 485783 rev

Explanation:

For 02-30 mm angular contact bearing, then

Since then

For a ball bearing, a=3 hence

Life at load 15 kN

Life load at 25.05 kN

In such a scenario, the Palmgren-Miner cycle ratio summation rule is expressed as

By substitution

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explanation:

answer:

just reverse the digits.

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