The size of carvins cove water reservoir is 3.2 billion gallons. approximately, 11 cfs of water is continuous withdrawn from this reservoir to support residents of roanoke county. this reservoir is filled with water from the roanoke river. during a severe drought, inflow into this reservoir can drop to 0.5 cfs. if the drought persists, how long (days) until this reservoir dry-up? (

471 days

Explanation:

Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons

As,  

1 gallon = 0.133 cubic feet (cf)

Therefore,  

Capacity of Carvins Cove water reservoir in cf  = 3.2 x 10˄9 x 0.133

                                                                         = 4.28 x 10˄8

Applying Mass balance i.e

Accumulation = Mass In - Mass out  (Eq. 01)

Here  

Mass In = 0.5 cfs

Mass out = 11 cfs

Putting values in (Eq. 01)

Accumulation  = 0.5 - 11

                         = - 10.5 cfs

Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.

Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600

                                                                                       = 37,800

Converting depletion of reservoir in cubic feet per day= 37, 800 x 24

                                                                                         = 907,200  

i.e. 907,200 cubic feet volume is being depleted in days = 1 day

1 cubic feet volume is being depleted in days = 1/907,200 day

4.28 x 10˄8 cubic feet volume will deplete in days  = (4.28 x 10˄8) x                    1/907,200

                                                                                 = 471 Days.

Hence in case of continuous drought reservoir will last for 471 days before dry-up.

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: