Problem 8:A forward Stirling gas cycle comprises the following four processes:1-2: constant volume2-3: polytropic with n= 13-4: constant volume 4-1: polytropic with n= 1If V1= 0.1 L, P2= 40 bar, V3= 2 L, and P4= 1 bar, determine the unknown pressures, P1and P3, the net work output in the cycle, Wnet, and net heat transferred in the cycle, Qnet. Plot the process on a P-vdiagram.

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

the answer is d

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)