A football player attempts a 30‐yd field goal. If he is able to impart a velocity u of 100 ft/sec to the ball, compute the minimum angle θ. for which the ball will clear the crossbar of the goal. (Hint: Let m = tan θ)

2.53°

Explanation:The ball is undergoing a projectile motion that is why it has an angle

Range = (U^2 sin2a)/g

U= velocity of the ball=100ft/sec

Range of the ball(i.e horizontal distance the ball crossed)= 30yard=90ft

a=angle the ball is projected

g= acceleration due to gravity=9.8m/s^2

90=(100^2×sin2a)/9.8

90×9.8=10000×sin2a

882/10000=sin2a

0.0882=sin2a

Sin^-1 0.0882=2a

5.06=2a

a=5.06/2

a=2.53

answer:

uygtfjyftujtfj

explanation: