A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg was used. Calculate the Brinell hardness (in HB) of this material.

HB=131.69      

Explanation:

Given that

Diameter ,    D= 10 mm

Depth of indentation ,d= 1.55 mm

Load ,P =500 kg

Brinell hardness is given as

Now by putting the values in the above equation we get

HB=131.69

Therefore the hardness of the material will be 131.69 HB.

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answer:

a

explanation: