Determine the maximum possible longitudinal separation which can exist between a geostationary satellite and an earth station while maintaining line- of-sight communications, assuming the minimum angle of elevation of the e station antenna is 5°. State also the latitude of the earth station.

Latitude = 76.33 degrees. Maximum Separation = 41,127.21Km

Explanation:

Parameters used:

1. Smax = Geo stationery satellite position with maximum slant range to the earth station

2. Smin = Geo stationery satellite position with minimum slant range to the earth

3. E = Earth station

4. C = Centre of the earth

5. Re= Radius of the earth = 6738.14km

6. Rs = Orbit radius of the satellite = 42164.17km

For a minimum elevation of 5°

CSmax/Sin 95° = CE/Sinξ

Therefore, Sin ξ = 6738.14Sin 95° /42164.17

ξ=8.667

ψ=180-95-8.667=76.33° latitude

Applying the sin law;

ESmax/Sinψ = CSmax/Sin95

Therefore; ESmax = CSmax(Sin76.33)/Sin95

ESmax = 42164.17*0.9717/0.9962

ESmax=41127.21Km

answer: 5

explanation:

6-1