5 L of air at 122 kPa and 20 oC was compressed by an air compressor applying 185 kJ/kg flow work increasing the pressure to 1,076 kPa. Calculate the final temperature in oC

The final temperature is 37.26 °C

Explanation:

Assuming the thermodynamic process is an adiabatic compression process.

T2 = T1(P2/P1)^k-1/k

T2 is the final temperature of air

T1 is the initial temperature of air = 20 °C

P1 is the initial pressure of air = 122 kPa

P2 is the final pressure of air = 1,076 kPa

k represents gamma = 1.4

T2 = 20(1,076/122)^1.4-1/1.4 = 20(8.8197)^0.4/1.4 = 20(8.8197)^0.2857 = 20(1.863) = 37.26 °C

answer:

a

explanation: