= 
→ 1
→ 2![\frac{d T}{d t}=\frac{wc}{mc}\left[T_{i}-T\right]+\frac{h p A_ P}{m c} \quad(T_w-T)](/tpl/images/0552/3820/f6dd3.png)
![\frac{d T}{d t}=\frac{w}{m} \left[T_{i}-T\right]+\frac{h p A_ P}{m c} \quad(T_w-T)](/tpl/images/0552/3820/5cd25.png)
= 
![T(s)=\frac{\left[\frac{w cT_i+h_{P} A_ P T_{w}}{m c}\right]}{\left(\frac{h_ P A _P}{mc}+S+\frac{w}{m}\right)}](/tpl/images/0552/3820/a2940.png)
is the value of steady state.
→ 1
→ 2
= 
→3
→ 4
= 
+ 
→ 5
→ 6
+ 
- For a steam-heated stirred-tank system modeled by the following equations:
mC dT/dt = w...
Engineering, 18.03.2020 19:31 QueenNerdy889
For a steam-heated stirred-tank system modeled by the following equations:
mC dT/dt = wC(Tᵢ - T)+hₚ Aₚ (Tᵥᵥ - T)
mᵥᵥ Cᵥᵥ dT_w/dt = hₛ Aₛ (Tₛ - T_w) - hₚ Aₚ (Tᵥᵥ - T)
Assume that the system temperature Tₛ and is constant.
(a) Find a transfer function relating tank temperature T and inlet liquid Tᵢ.
(b) What is the steady-state value for this choice of input and output?
Answers: 1
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