A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with specific gravity of 1.7. The manometer reading is 320 mm. What is the pressure difference

Answer :pressure difference is Δp=5,32pa

Explanation : the expression for pressure difference at the top of the manometer can be given as

P1-P2=Rg(ρm-ρs) 1

For gases, ρs is negligibly small when compared to ρm . So substitute zero for in equation (1) and re-write the final expression

Δp=Rg(ρm)

Here,

Δp is the differential pressure applied to manometer in Pa or psi

R is the difference in the levels of the two interfaces in meters 320mm

To metre =0.320m

g is the acceleration of gravity

ρm is the manometer liquid density in 9.81m/s²

Specific gravity(sg) of liquid 1.7

Density of water is 997 kg/m³

Sg=density of substance/density of water

1.7=density of substance/997

Density of substance=1.7*997

=1694.9kg/m³

Hence solving for pressure difference

Δp=Rg(ρm)

=0.320*9.81*1694.9

Δp=5,32pa

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