A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane-strain fracture toughness of ( ) and a yield strength of 860 MPa (125,000 psi). The flaw size resolution limit of the flaw detection apparatus is 3.0 mm (0.12 in.). If the design stress is one-half the yield strength and the value of Y is 1.0, determine whether a critical flaw for this plate is subject to detection.

In the question, the plane-strain fracture toughness (K) is missing. The value is 98.9Mpa√m

The critical flaw can be detected since A_c = 16.84mm is much more greater than the flaw detection Apparatus's resolution limit of 3mm.

Explanation:

Length of surface creek (A_c) is given as;

A_c = (1/π)(K/Yσ)

Where K is toughness

σ is Yield strength

Frim question, Y = 1

Thus,

A_c = (1/π)(98.9Mpa√m/(1 x 860/2))²

A_c = (1/π)(98.9²m/(430²) = 0.01684

= 16.84mm

The critical flaw can be detected since A_c = 16.84mm is much more greater than the flaw detection Apparatus's resolution limit of 3mm.

answer: 500 wph.

explanation:

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

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