A well pumps at 400 L/s from a confined aquifer whose thickness is 24 m. If the drawdown 50 m from the well is 1 m and the drawdown 100 m from the well is 0.5 m, then calculate the hydraulic conductivity and transmissivity of the aquifer. Do you expect the drawdowns at 50 m and 100 m from the well to approach a steady state? Explain your answer. If the radius of the pumping well is 0.5 m and the drawdown at the pumping well is measured as 4 m, then calculated the radial distance to where the drawdown is equal to zero. Why is the state-state drawdown equation not valid beyond this distance?

the calculations and their justification are found in the explanation section.

Explanation:

The average transmissivity is

Qw = pumping rate = 400 L/s = 400000 m³/s

s₁ = drawdown of the well = 1 m

s₂ = 0.5 m

r₁ = piezometric level = 50 m

r₂ = 100 m

Replacing values

the hydraulic conductivity is

b = thickness = 24 m

Replacing

no steady state for this drawdown.

The radial distance is

here

sw = 4 m = drawdown at the pumping well

s =drawdown of the radial distance = 0

rw = radius of the pumping well = 0.5

Clearing r

It can be said that the steady state reduction is not valid at a distance beyond that calculated because the reduction would become negative.

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

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explanation: