The driveshaft of an automobile is being designed to transmit 134 hp at 2900 rpm. Determine the minimum diameter d required for a solid steel shaft if the allowable shear stress in the shaft is not to exceed 6100 psi.

The minimum diameter is 1.344 in

Explanation:

The angular speed of the driveshaft is equal to:

Where

N = rotational speed of the driveshaft = 2900 rpm

The torque in the driveshaft is equal to:

Where

P = power transmitted by the driveshaft = 134 hp = 73700 lb*ft/s

The minimum diameter is equal to:

Where

T = shear stress = 6100 psi

τ = 242.68 lb*ft = 2912.16 lb*in

post office i thinkexplanation:

explanation:

which ordered pair is not in the solution

y > -1/2x + 5

y ≤ 3x - 2

a) (5,3) b) (4,3)

c) (3,4) d) (4,4)