A pressure vessel of 250-mm inner diameter and 6-mm wall thickness is fabricated from a 1.2-m section of spirally welded pipe AB and is equipped with two rigid end plates. the gage pressure inside the vessel is 2 MPa, and 45-kN centric axial forces P and P' are applied to the end plates. Determine a) the normal stress perpendicular to the weld b) the shearing stress parallel to the weld.

Missing Diagram is attached.

a) 21.43 MPa

b) -14.2 MPa

Explanation:

Given:

Calculating the stresses:

= 41.667 MPa

= 20.833 MPa

-9.325 MPa

For stress along x axis:

Tx = Tl - Ta

= 20.83 - 9.325

= 11.5 MPa

= 26.58 MPa

= -15.08 MPa

Mohr's circle angle = 2∅

= 2 * 35°

= 70°

a) for normal stress perpendicular to weld, we have:

Tx' = Tavg + Tmax (cos70°}

= 26.590 - 15.08(cos70°)

= 21.43 MPa

b) shearing stress parallel to weld:

= Tmax (sin70°}

= -15.08 sin70°

= -14.2 MPa

this is true

explanation:

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