1. The water-gas-shift reaction, CO(g) + H2O(g)  CO2(g) + H2(g) is carried out with the reactants consists of 2 mol of H2O vapor and 1 mol of CO. The temperature is 1,100 K and the pressure is 1 bar. 1). Find out the reaction constant K from the Figure13.2 on the textbook based on the condition given. (5 points) 2). Calculate the fraction of steam reacted. Assume the mixture behaves as an ideal gas. (10 points)

Answer (a) K=1

            (b) 1/3  fraction of steam reacted

Explanation:

CO  + H20 → CO2 + H2

t=0   (1/v)   (2/v)

t= teq   (1-a/v)   (2-a/v)   (a/v)  (a/v)

k= (a/v)²/ (1-a/v)(2-a/v)

1 = a²/(1-a)(2-a)

2-a - 2a + a²= a²

2 = 3a

a = 2/3

Moles of H2O reacted ; a=2/3

Fraction of H2O reacted ; 2/3

                                             2                  = 1/3

1/3 fraction of H20 reacted

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