Heat is transferred at a rate of 2 kW from a hot reservoir at 875 K to a cold reservoir at 300 K. Calculate the rate at which the entropy of the two reservoirs changes. (Round the final answer to six decimal places.) The rate at which the entropy of the two reservoirs changes is kW/K. Is the second law satisfied?

The correct answer is 0.004382 kW/K, the second law is a=satisfied and established because it is a positive value.

Explanation:

Solution

From the question given we recall that,

The transferred heat rate is = 2kW

A reservoir cold at = 300K

The next step is to find the rate  at which the entropy of the two reservoirs changes is kW/K

Given that:

Δs =  Q/T This is the entropy formula,

Thus

Δs₁ = 2/ 300 = 0.006667 kW/K

Δs₂ = 2 / 875 =0.002285

Therefore,

Δs = 0.006667 - 0.002285

= 0.004382 kW/K

Yes, the second law is satisfied, because it is seen as positive.

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

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