Engineering, 07.05.2020 03:10 donuteatingcat
The voltage across a 5mH inductor is 5[1-exp(-0.5t)]V. Calculate the current through the inductor and the energy stored in the inductor at t=2 seconds
Answers: 1
![i(t) = \frac{1}{0.005} \int_0^t \mathrm{5(1-e^{-0.5t}}) \,\mathrm{d}t \,+ 0\\\\i(t) = 200 \int_0^t \mathrm{5(1-e^{-0.5t}}) \,\mathrm{d}t \\\\i(t) = 200 \: [ {5\: (t + \frac{e^{-0.5t}}{0.5})]_0^t \\i(t) = 200\times5\: \: [ { (t + 2e^{-0.5t} + 2 )] \\](/tpl/images/0651/3489/5ea6f.png)
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The voltage across a 5mH inductor is 5[1-exp(-0.5t)]V. Calculate the current through the inductor an...
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