Calculate the optimum elevation and the piping network so that the system becomes most profitable. For each batch, the company spends $502 in labor, transport and materials, but gets $645 as revenue. The time required for a batch is summation of the time to fill and time to drain, as instantaneous reaction does not require any settling time as long as A and B are fed in same rates. The operation cost also involves expenses for running two pumps pumping reagents A and B in the inlet, where the industrial rate for energy is 50cents per kilo-watt-hour (note the unit). Fortunately, there is no investment cost, as the company got zero interest loan --- so you do not have to worry about it. Try to design the elevation for maximum profit. If you have the tank elevation too high, the energy cost will reduce your profit. On the other hand, too low elevation would drain the tank slowly causing loss of revenue. Also, indicate the piping lay-out while computing the optimum elevation. At the same time, give an estimate of the annual profit assuming the tank will be continuously fed. Use the following values for your calculations. The densities of A, B and C are 900kg/m^3, 1400kg/m^3 and 1100kg/m^3 (those who are concerned about mass conservations in the reaction should note a gas also escapes during the reaction). Take friction factor of all pipes to be 0.0125 for turbulent flows. There are no minor losses. The efficiency of the pumps is 0.8.