The bar has a cross-sectional area of 400×10^-6 m². If it is subjected to a uniform axial distributed loading along its length and to two concentrated loads determine the average normal stress in the bar as a function of X for 0.5 m < x <= 1.25m

the average normal stress in the bar is :

Explanation:

The free body flow of the missing diagram is attached to the answer below.

From the information given:

Let consider the sum of forces along horizontal direction to be equal to zero.

The average normal stress in the bar can be calculated by the formula:

where;

average normal stress in the bar

A = cross sectional area in the bar and it is given by:

N = (13- 8x) kN

∴

Thus; the average normal stress in the bar is :

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explanation:

answer:

just reverse the digits.

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