the current in the inductor is relative to the voltage across the inductor. A : lagging by less than 1/4 of a cycle B : in phase C : leading by less than 1/4 of a cycle D : lagging by 1/4 of a cycle E : leading by 1/4 of a cycle

  D : lagging by 1/4 of a cycle (ideal inductor)

Explanation:

The rate of change of current in an inductor is proportional to the voltage across the inductor. Hence voltage must increase before current can. That means current in an inductor lags the voltage across it.

For an ideal inductor (with no effective series resistance), the lag will be 1/4 cycle of a sinusoidal waveform.

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If the inductor has internal losses (resistance), then the lag will be less than 1/4 cycle.

Comment on the problem

No circuit image or other description of the inductor is provided here, so we don't know that the inductor is ideal.

answer:

sure does

explanation: