a steal bar with 1 in diameter has been subjected to a tensile force of 3 tons find tensile stress in the bar

stress = 8,556 Psi.   or  (stress = 59 Mpa)

Explanation:

stress = force / area

force P = 3 tons (convert to lbs. for units consistency)

1 ton = 2240 lbs.

P = 6,720 lbs.

steel bar Diameter D = 1 in. (convert to d

Area of steel bar = (π *  1²) / 4 = 0.785 in²

therefore, stress = 6720 lbs. / 0.785 in²

stress = 8,556 Psi.

in Mpa 8556 Psi * 0.00689476 MPa/Psi = 59 Mpa

answer:

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answer:

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