Determine the voltage across a 2-μF capacitor if the current through it is i(t) = 3e−6000t mA. Assume that the initial capacitor voltage is zero g

mV

Explanation:

The voltage across a capacitor at a time t, is given by:

                ----------------(i)

Where;

v(t) = voltage at time t

= initial time

C = capacitance of the capacitor

i(t) = current through the capacitor at time t

v(t₀) = voltage at initial time.

From the question:

C = 2μF = 2 x 10⁻⁶F

i(t) = 3 mA

t₀ = 0

v(t₀ = 0) = 0

Substitute these values into equation (i) as follows;

            [Solve the integral]

Therefore, the voltage across the capacitor is mV

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explanation:

answer:

a

explanation: