A specimen of some metal having a rectangular cross section 9.18 mm x 13.2 mm is pulled in tension with a force of 3310 N, which produces only elastic deformation. Given that the elastic modulus of this metal is 79 GPa, calculate the resulting strain.

0.0000084

Explanation:

Given data:

Cross sectional area = 9.18mm*13.22mm

Force N = 3310

Elastic modulus = 79 GPa

Solution:

Area = 9.18mm * 13.22mm

= 121.36mm^2

= π(d)^2

= π(0.121)^2

= 0.05m^2

Stress = F/A

= 3310N/0.05m^2

= 66200Nm^2

Strain = Stress/ modulus of elastic

= 66200/7.9*10^10

= 0.0000084

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explanation:

answer:

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