A cylinder 10 mm in diameter is pulled with a stress of 150 MPa. The diameter elastically decreased by 0.007 mm. Determine Poisson's ratio if the material has a elastic modulus of 100 GPa.

Poisson's Ratio,μ =  0.46

Explanation:

Poisson's Ratio is calculate as

μ = transverse/ longitudinal strain 

μ = -  εt / εl                          

where

μ = Poisson's ratio

εt = transverse strain

εl = longitudinal  strain  

Transverse strain can be expressed as

εt = change in diameter / initial diameter                            

where

εt =transverse  strain  

change in diameter=0.007mm

initial diameter = 10mm

εt =0.007mm/ 10mm= 0.0007

Longitudinal strain can be expressed as

εl=Stress/ elastic modulus =  σ/ E

= Stress = 150 MPa ,  converting to GPa becomes 150/1000 = 0.15 GPa

εl=  0.15 GPa / 100  GPa= 0.0015

Poisson's Ratio,μ = transverse/ longitudinal strain

( 0.0007 /0.0015) = 0.46 =0.46

answer:

a

explanation: