A quantity of gas has a pressure of 1.39 atm and a volume of 6.95 L. What is the volume of this gas when the pressure is changed to 740 mm Hg?

The volume of the quantity of gas when the pressure changes to 740 mm Hg is approximately 9.92 L

Explanation:

The properties of the quantity of gas are;

The initial pressure of the gas, P₁ = 1.39 atm

The initial volume of the given volume of gas, V₁ = 6.95 L

The final pressure of the quantity of gas, P₂ = 740 mmHg

Boyle's Law states that at constant temperature, the pressure, P, of a given mass of gas is inversely proportional to its volume, V

Mathematically Boyle's Law can be written as follows;

Therefore, we have;

P₁·V₁ = P₂·V₂

Where;

V₂ = The final volume of the quantity of gas when the pressure changes to 740 mm Hg

By substituting the known values, we have;

The final volume of the quantity of gas when the pressure changes to 740 mm Hg = V₂ ≈ 9.92 L

answer:

just reverse the digits.

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