Choose K, z and p so that the closed-loop system G(s) has a maximum of 10% overshoot to a step input and a 1% settling time of no more than 1.5sec. Do not attempt any pole/zero cancellation! Recall that when a pole is very close to a zero, the effects of the two are nearly cancelled in the output. Hint: Review lecture notes on System Zeros. Verify your design using Matlab by plotting a step response of your closed-loop system. Print the step response and attach it to your homework. C(s)= K(s+z)/s+p , P(s)= 1/s(s+3)

At steady state, air at 200 kpa, 325 k, and mass flow rate of 0.5 kg/s enters an insulated duct having differing inlet and exit cross-sectional areas. the inlet cross-sectional area is 6 cm2. at the duct exit, the pressure of the air is 100 kpa and the velocity is 250 m/s. neglecting potential energy effects and modeling air as an 1.008 kj/kg k, determine ideal gas with constant cp = (a) the velocity of the air at the inlet, in m/s. (b) the temperature of the air at the exit, in k. (c) the exit cross-sectional area, in cm2