A structural component is fabricated from an alloy that has a plane strain fracture toughness of 45 MPam. It has been determined that this component fails at a stress of 300 MPa when the maximum length of a surface crack is 0.95 mm. What is the maximum allowable surface crack length (in mm) without fracture for this same component exposed to a stress of 300 MPa and made from another alloy with a plane strain fracture toughness of 67.5 MPam

Explanation:

From the given information:

The first thing we need to do is to use the formula used in-plane strain fracture toughness to determine the geometry factor

i.e

where;

a = crack length

geometry factor

In the first scenario, where;

Plain fracture toughness

radius(R) = 3.142

Then, replacing it into the above equation, we have:

Now, since we've determined the geometry factor, it will be easier to estimate the max. allowable surface length.

∴

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

true

explanation: