A cargo ship with LBP 134 m floats at 4.6 m and 4.2 m draught at FP and AP respectively. The centre of flotation is 2 m fwd of amidships and MCTC is 120 tonnes. M. Determine the position of 200 t of cargo to be loaded (from amidships) to ensure the ship floating in even keel condition after the loading completed.

4.2019 mts , 4.598 mts

Explanation:

center of flotation = 2 m fwd.

MCTC = 120 tonnes

Determine the position of  200 t of cargo to be loaded

first step : determine the change trim = trimming moment / MCTC

                                                              = 134 * 1 / 120 = 0.11 mts

∴ бtf = 0.11 * ( 2/100 ) = 0.0022 mts ( given that the ship trims forward )

бtf = - 0.0022 mts

also ; бTa = 0.0019 mts (  + due to increase in draught )

determine the Final position

Ta = 4.2 ( draught at AP )  + бTa

     = 4.2 +  0.0019

     = 4.2019 mts

T = 4.6 ( draught at Fp )  + бtf

                                = 4.6 + ( - 0.0022 )  = 4.598 mts

answer:

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explanation: