A transformer for charging a power tool steps the line voltage down to 2.9 V. The output current of this transformer is 240 mA. If the transformer is ideal (100% efficient), what is the input current

The input current is 5.8 mA

Explanation:

Given;

output voltage of the transformer, V₀ = 2.9 V

output current of the transformer, I₀ = 240 mA = 0.24 A

efficiency of the transformer, E = 100%

the electrical outlet of most homes is 120 V = input voltage

The input power is calculated as follows;

input power = IV

where;

V is input voltage

I is input current

I x 120 = 0.696

I = 0.696 / 120

I = 5.8 x 10⁻³ A

I = 5.8 mA

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