An intelligence signal is amplified by a 65% efficient amplifier before being combined with a 250W carrier to generate an AM signal. If it is desired to operate at 50% modulation, what must be the dc input power to the final intelligence signal amplifier

"192.3 watt" is the right answer.

Explanation:

Given:

Efficient amplifier,

= 65%

or,

= 0.65

Power,

As we know,

⇒

By putting the values, we get

Now,

⇒

DC input (0.65) will be equal to "".

hence,

The DC input power will be:

=

=

=

answer:

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answer:

truck

explanation:

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